Rodada positionIntroductory diagram: the cue ball hits ball 2 and travels right long cushion → top short cushion → left long cushion to ball 3 in the bottom-right corner. No values are given in this introductory example.
Bola-Efecto: Rodada · Drill cards
Lane = 6 − Ball 2 (long cushion) + Ball 2 (short cushion) + Offset; then the lane is changed with steps of spin and ball fraction
6 − 3 + 0 = lane 3Ball 2 position (right long cushion): 3Lane: 3Standard (6 ball, S spin). Larga 3, corta 0, offset 0 → 6 − 3 + 0 + 0 = lane 3. But ball 3 is in the corner, i.e. on lane 2.
3 ⇒ S−1 ⇒ lane 2Spin step: S−1 (−1 lane)Ball 2 position (right long cushion): 3Lane: 2The calculation gives lane 3, and ball 3 is in the corner (lane 2). To drop one lane, lower the spin by one step: S−1 → 3 − 1 = 2. The ball stays at 6.
6 − 4 + 0 − 2 = 0 ⇒ S+1 = lane 1Offset (shift): -2Spin step: S+1 (+1 lane)Ball 2 position (right long cushion): 4Lane: 1Larga 4, corta 0, offset −2 → 6 − 4 + 0 − 2 = lane 0. Spin S+1 gains one lane → lane 1. Ball 6.
6 − 4 + 0 − 2 = 0 ⇒ S+2 + B+1 = lane 3Ball fraction (thickness): 3 — B+1 (+1 lane)Offset (shift): -2Spin step: S+2 (+2 lanes)Ball 2 position (right long cushion): 4Lane: 3Same position, another solution: lane 0; spin S+2 (+2) and ball 3 (B+1, +1) → 0 + 2 + 1 = lane 3.